2x^2+18x=960

Solution for 2x^2+18x=960 equation:

2x^2+18x=960

We move all terms to the left:

2x^2+18x-(960)=0

a = 2; b = 18; c = -960;
Δ = b2-4ac
Δ = 182-4·2·(-960)
Δ = 8004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8004}=\sqrt{4*2001}=\sqrt{4}*\sqrt{2001}=2\sqrt{2001}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{2001}}{2*2}=\frac{-18-2\sqrt{2001}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{2001}}{2*2}=\frac{-18+2\sqrt{2001}}{4}
$